Redox & Non Redox Titrations Class 11 | JEE Main & Advanced

JEE Nexus by Unacademy・2 minutes read

The text discusses the importance of understanding titrations, emphasizing the significance of equivalence points, indicators, and accurate calculations for precise results in chemical reactions. It delves into the process of converting molarity to normality, using formulas for calculating equivalents, and balancing redox reactions with the N factor to ensure accurate outcomes.

Insights

  • Understanding the distinction between molarity and normality is crucial for accurate chemical calculations, with specific formulas provided for conversion.
  • The significance of using equivalent concepts in predicting and solving questions related to titres is emphasized, aiding in complex chemistry problem-solving.
  • The importance of double indicator titrations in redox reactions is highlighted, with a focus on equivalence points and the role of indicators like phenolphthalein and methyl orange.
  • The text stresses the necessity of precise calculations and understanding the N factor in acid-base titrations, ensuring accurate results in chemical reactions.
  • Practical instructions and examples are provided for calculating equivalents based on N Factor and molarity into volume conversions, demonstrating the application of theoretical concepts in chemical reactions.

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Recent questions

  • What is the significance of titres in chemistry?

    Titres in chemistry are crucial measurements used to determine the concentration of a substance in a solution. They involve precise techniques like titration to find the exact amount of a reactant needed to complete a reaction. Titres play a vital role in various chemical analyses, especially in determining unknown concentrations or verifying the purity of substances. Understanding titres is essential for accurate calculations and ensuring the success of chemical reactions.

  • How do you differentiate between molarity and normality?

    Molarity and normality are both concentration units used in chemistry, but they differ in their definitions and applications. Molarity is the measure of the number of moles of solute per liter of solution, while normality is the measure of the number of equivalents of a substance per liter of solution. Equivalents take into account the chemical activity of a substance, especially in acid-base reactions. It is crucial to understand this distinction to make accurate calculations and predictions in various chemical processes.

  • What is the role of indicators in redox titrations?

    Indicators play a crucial role in redox titrations by helping to detect the endpoint or equivalence point of the reaction. In redox titrations, indicators like phenolphthalein and methyl orange change color at specific pH ranges, indicating the completion of the reaction. These color changes signal the balance between the oxidizing and reducing agents, ensuring accurate titration results. Understanding the behavior of indicators is essential for determining the endpoint in redox titrations and achieving precise measurements in chemical analyses.

  • How are equivalents calculated in chemical reactions?

    Equivalents in chemical reactions are calculated based on the concept of equivalence factors, which consider the chemical activity of substances. To determine equivalents, one must convert moles of a substance to molarity and then to volume based on the molar volume and n factor. Equivalents are crucial in balancing reactions, especially in acid-base titrations, to ensure the correct stoichiometry and completion of the reaction. Accurate calculations of equivalents are essential for predicting outcomes and understanding the chemical behavior of substances.

  • What is the significance of the N factor in acid-base titrations?

    The N factor, or normality factor, is a crucial parameter in acid-base titrations that helps determine the number of equivalents of a substance involved in a reaction. It plays a vital role in calculating moles, volumes, and equivalents of reactants, ensuring the proper stoichiometry and completion of the titration process. Understanding the N factor is essential for accurate measurements, predicting reaction outcomes, and balancing chemical equations effectively. The N factor is a fundamental concept in acid-base titrations that guides the calculation of concentrations and the determination of unknown substances in chemical analyses.

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Summary

00:00

"Titres, Redox, and Top Resources Discussed"

  • The session focuses on titres, addressing sorrows and pains in one place.
  • A special Titan's session on redox is highlighted.
  • The importance of keeping the butt from the top of the head is emphasized.
  • The availability of the J Advanced answer key on the website is mentioned.
  • The chapter on titres in chemistry is discussed, known for its complexity.
  • The significance of using equivalent concepts in predicting questions related to titres is stressed.
  • Details about an offer for an ITG subscription at a low fee with an extension are provided.
  • The necessity of utilizing top resources like Josie Verma's books for self-improvement is emphasized.
  • Instructions on taking action, studying diligently, and not compromising on resources are given.
  • Information about a subscription offer for live classes and tests for the batch of 2026 is shared.

18:52

Converting Molarity to Normality: Essential Formulas

  • The process involves converting molarity to normality by multiplying molar mass by a factor and then multiplying normality by volume.
  • It is crucial to differentiate between molarity and normality, ensuring the correct calculations are made.
  • The formula for converting molarity to volume involves multiplying both sides by a factor.
  • Understanding the concept of equivalents is essential, with normality being equivalent to molarity defined by volume of solution in liters.
  • The ideal gas volume for one mole of gas is 22.4 liters at NTP conditions, aiding in calculations.
  • Equivalents can be determined by dividing the given volume by the equivalent volume, which is the molar volume divided by the n factor.
  • The formula for equivalents involves the given weight divided by the equivalent weight, with moles converted to molarity and then to volume.
  • The molar volume represents the volume of gas for one mole at NTP conditions, simplifying calculations.
  • The process includes converting given weight to molarity, then to volume, and finally determining equivalents based on the molar volume and n factor.
  • Understanding and applying these formulas accurately is crucial for precise calculations in the given context.

45:42

Molar Volume Calculations in Electro Chemistry

  • The process involves converting normality into volume, which can be expressed as molarity.
  • A formula is derived from molecular weight and equivalent weight, leading to molar volume calculations.
  • The relationship between molar volume, equivalent weight, and a factor is crucial in the formula.
  • Four key formulas are consolidated for use in Electro Chemistry.
  • The distinction between normality and molarity is proven through equivalent factors and moles.
  • Acid-base titrations are corrected for strong acids and bases, focusing on non-redox titrations.
  • Double indicator titrations are emphasized for redox titrations, with indicators like phenolphthalein and methyl orange.
  • The importance of equivalence points in redox titrations is highlighted, with oxidizing and reducing agents balancing.
  • The role of indicators near equivalence points is explained, ensuring accurate titration results.
  • The neutral point in titrations is discussed, differentiating it from equivalence and endpoint points.

01:14:39

"Chemical reactions and conversions simplified"

  • Comminution needs to be understood with patience and ease.
  • Reactants in a reaction need to be combined to make the process easier.
  • Non-redox reactions are simpler than redox reactions.
  • Understanding the conversion of reactants in different mediums is crucial.
  • Calculating equivalent weight involves dividing molecular weight by the factor.
  • Different reactions and conversions are discussed, such as Fe2 to Fe+3 and MnO4 to Mn2.
  • Extracting the N factor is essential for various reactions.
  • Different oxidation states and conversions are detailed, like Cr2 to Cr3.
  • The importance of understanding the N factor and its application in solving problems is emphasized.
  • Equivalence of oxidant and reducing agent is crucial in titration processes.

01:33:35

Calculating Equivalents and Volumes in Chemistry

  • The text discusses the concept of A Factor in moles, with a focus on factors like N Factor and money calculations.
  • It emphasizes the importance of factoring out moles and determining costs based on factors like N Factor.
  • The text delves into the calculation of moles of various substances, such as Oxalate and chromate, in terms of their equivalence.
  • It highlights the significance of understanding the N Factor and equivalence of substances like Oxalate and Oxidol.
  • Practical instructions are provided on how to calculate equivalents based on N Factor and molarity into volume conversions.
  • The text guides on determining the volume of substances like K2S2O7 and K2Cr2O7 through molarity and N Factor calculations.
  • It explains the process of calculating equivalents and volumes for substances like Ferrous Oxalate in different scenarios.
  • The text details the steps involved in calculating the volume of substances like K2S2O7 in acidic mediums.
  • It provides instructions on determining equivalents for substances like KMnO4 in reactions involving acidic mediums.
  • The text concludes with practical examples and calculations to illustrate the application of N Factor and equivalence in various chemical reactions.

01:54:51

Calculating Milliequivalents in Chemical Reactions

  • To find the equivalent of Milli Elen of Let's take 4 and search for 100.
  • A factor of 5 into molarity power in volume gives 0.05 as the equivalent.
  • The volume used should be in liters to get the equivalent.
  • When considering 100 A, 50 A is used, resulting in 60 milliequivalents.
  • The N factor is one, so 50 millimoles are required.
  • The value of Fe2 will be found in the same case as k27.
  • For Oxalate Oxidant, molarity is 0.1, volume is 25, and milliequivalents are 7.5 ml.
  • The N factor of f24 is 5, resulting in 12.5 milliequivalents.
  • The equivalent of f24 is calculated by dividing the weight by the equivalent weight.
  • To remove Oxiderm Gram Etch Off Ferrous oxalate, the total volume of 0.1 A kmno4 needed is calculated to be approximately 53 liters.

02:15:09

Iodometric Titration: Equivalents and Molarity Calculations

  • To extract the text, L was not used, everything was given in liters.
  • The equivalents of two pairs were added, resulting in the equivalent of ke ph and ken.
  • The equivalent of na4 plus h24 was calculated to be 4.
  • The A factor for both A4 and ken was the same, resulting in an equivalent of 4.
  • The equivalents of f of four were found to be four.
  • The equivalent of k4 was determined by adding the equivalents of na2 c24 and h2 c24.
  • The process of iodometric titration involves the reduction of free iodine to iodide and the oxidation of iodide to free iodine.
  • Iodometric titration is standardized against sodium thiosulfate.
  • The normality of na2 a3 was calculated by equating it with the equivalents of kb3.
  • The molarity was calculated by multiplying the normality by the volume.

02:35:44

"Acid-base mixing in Cofirex language"

  • Cofirex is a spoken language known as Ijli.
  • Equivalence point is reached through negotiations during the mixing process.
  • Acid-base mixing with a burette is crucial for the right balance.
  • Transactions are conducted following a specific arrangement.
  • Adding Barod drop by drop is essential for accuracy.
  • Careful use of buckets and mugs is advised during mixing.
  • Acid-base titration involves finding unknowns through equalization.
  • The concentration of solutions determines neutrality.
  • N factor calculation is vital for non-redox reactions.
  • Partial and complete transfers of species impact N factor calculations.

02:59:19

"Balancing Acidic Compounds for Accurate Reactions"

  • The text discusses the transfer of rights between acidic compounds, specifically h33, hp4, and h3 p2.
  • It mentions that if only two rights are available, a maximum transfer should be made.
  • A transfer is detailed from h3 p2 to h33, with the correct visibility of all three compounds.
  • The text delves into a conversation and reaction between compounds A and h3 p2, leading to the disappearance of h p.
  • It highlights the importance of balancing compounds like h2o in reactions.
  • The text introduces the concept of finding the oxidation number of hydrogen and its equivalent in reactions.
  • It emphasizes the significance of N factor in acid-base titrations and the calculation of moles in reactions.
  • The text discusses the balancing of reactions to ensure proper transfer of electrons and the importance of N factor in determining equivalents.
  • It explains the process of finding N factor for different species in reactions and the significance of balancing equations.
  • The text concludes by stressing the importance of following the correct method in calculations and balancing reactions for accurate results.

03:22:18

Factors and Equivalence Points in Titration

  • The mole equivalent for a factor of two and two annas should be the mole.
  • To find the factor A, the product of both factors should be two.
  • The most common factors are H2 and scan, but one must be cautious in such questions.
  • The use of BaCl2 and H3PO4 is helpful in determining factors.
  • The n factor of BaCl2 is +2, and its equivalent is six.
  • The molar ratio of 1:3 results in a factor ratio of 3:1.
  • The double indicator titration involves understanding the equivalence point and the pH changes.
  • The equivalence point is where the acid and base meet, causing a rapid change in pH.
  • The number of vertical regions in the titration curve indicates the number of equivalence points.
  • The n factor of acids and bases must be considered in titration analysis.

04:02:25

Graphs Show Buffer Solutions and Equivalence Points

  • Two equivalence points are visible in the graph, the first and second equivalence points.
  • The nature of the graph shows a region where the pH remains constant, indicating a buffer solution.
  • The graph displays a rapid rise and fall, influenced by the base's n factor.
  • The behavior of the graph repeats itself, creating buffer solutions repeatedly.
  • The graph's nature changes with the addition of acid and base, showcasing resistance to pH changes.
  • The use of double indicators helps in understanding the titration process.
  • Indicators like phenolphthalein and methyl orange are used to detect color changes in specific pH ranges.
  • The color change range for methyl orange is from yellow to orange-red below pH 3.1.
  • Phenolphthalein changes color in the pH range of 8.3 to 10, indicating the equivalence point.
  • Understanding the behavior of indicators is crucial for accurate titration and pH detection.

04:22:56

Color Indicators Detect Equivalence Points in Chemistry

  • The equivalence point is indicated by a visible color change on the pH value.
  • The indicator's color change range determines whether the solution is at the equivalence point.
  • At the equivalence point, the entire area below is colorless with no color variation.
  • Indicators like phenol red change from colorless to pink near the equilibrium point.
  • The color change range for phenol red is 8.3 to 10, turning from colorless to pink.
  • Methyl orange's range is 3.1 to 4.4, changing from orange-red to red.
  • Phenol red indicates the first equivalence point, while methyl orange indicates the second.
  • Phenol red is used near the first equivalence point for color change detection.
  • Methyl orange is used after the first equivalence point to detect the second.
  • The reaction at the first equivalence point involves Na2CO3 reacting with H2S to form NaClO3.

04:48:01

"Indicator Volume Determines Acid Molarity Calculations"

  • Phenol fun and methyl range can be detected in reactions.
  • A solution is prepared with A, A2, and C3, with a focus on the molarity of the acid.
  • The volume of AC used is crucial in determining the amount of NaCO3 to be used.
  • Calculations are based on molar mass, with 10.6 grams of NaCO3 used in the solution.
  • The volume of sal use is determined based on whether only phenol fun or methyl orange is used.
  • Equivalents of Na2CO3 are calculated based on the reaction and molar ratios.
  • The volume of AC used varies depending on the indicator, with different calculations for phenol fun and methyl orange.
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