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Cengage illustration 6.55 Newtons Law's of Motion IIT JEE Advanced 2025

Cosmo Physics・2 minutes read

A rod of length "l" at an angle theta with the horizon shows a decreasing derivative with a negative sign. Applying the Pythagorean theorem results in x^2 + x^2 = 2, and solving for v simplifies to v = b.

Insights

  • The angle theta between a rod of length "l" and the horizon impacts the function's derivative, causing it to decrease with a negative sign.
  • Applying Pythagoras' theorem, the equation x^2 + x^2 = 2 can be solved to provide insights into mathematical relationships and calculations.

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Recent questions

  • What is the Pythagorean theorem?

    The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

  • How is the angle of a rod measured?

    The angle of a rod is measured in relation to the horizon, with the length of the rod being "l" and the angle being denoted as theta.

  • What does a decreasing derivative with a negative sign indicate?

    A decreasing derivative with a negative sign suggests that the function is decreasing at that point, meaning the slope of the function is negative and the function is trending downwards.

  • How is velocity calculated in the given equation?

    To calculate velocity in the equation -v + b = 0, where v is the velocity and b is a constant, you would solve for v by rearranging the equation to isolate v, resulting in v = b.

  • What does it mean for a function to have a negative derivative?

    A negative derivative of a function indicates that the function is decreasing at that point, meaning the slope of the function is negative and the function is trending downwards.

Related videos

Summary

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"Rod angle, decreasing derivative, Pythagorean solution"

  • Rod of length "l" makes an angle theta with the horizon
  • Derivative of the function is decreasing with a negative sign
  • According to Pythagoras, x^2 + x^2 = 2
  • Solve for v: -v + b = 0, v = b
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