WORK, ENERGY AND POWER in One Shot - From Zero to Hero || Class 9th

Physics Wallah Foundation2 minutes read

The Wala Foundation offers a free YouTube course for ninth graders, focusing on Physics, particularly Chapter 11 on "Work and Energy," which highlights the interconnectedness of concepts such as force, displacement, and the angle of application in determining work done. The text emphasizes the necessity of understanding foundational principles and the mathematical relationships governing work, energy, and their transformations, while encouraging active engagement with the content for deeper comprehension.

Insights

  • The Wala Foundation YouTube channel provides a free and extensive course for ninth graders, featuring one-shot videos on subjects like Physics, English, and Maths, with content being gradually uploaded for each chapter.
  • Currently, the focus is on Chapter 11 of the NCERT syllabus, "Work and Energy," which stresses the need for students to review earlier chapters on motion and gravity to build a solid understanding of the interconnected concepts.
  • In physics, work is defined as the product of force applied to an object and the displacement of that object in the direction of the force, highlighting that both force and displacement must occur for work to be considered done.
  • The formula for calculating work is W = F * d * cos(θ), where W represents work, F is force, d is displacement, and θ is the angle between the force and displacement vectors, emphasizing the importance of direction in these calculations.
  • Work can be categorized into positive work, negative work, and zero work, depending on the relationship between force and displacement; positive work occurs when they are in the same direction, while negative work occurs when they are in opposite directions.
  • The text clarifies that work is a scalar quantity, meaning it does not have directionality like vectors do, even though it is derived from the multiplication of vector quantities (force and displacement).
  • The concept of energy is explored, with kinetic energy defined as the energy of motion, and the work-energy theorem stating that the work done on an object equals the change in its kinetic energy, reinforcing the relationship between work and energy.
  • Potential energy is introduced as energy stored when work is done on an object, with the amount of potential energy increasing as the height of the object increases, quantified by the formula PE = mgh.
  • The discussion concludes with the law of conservation of energy, which states that energy cannot be created or destroyed, only transformed, emphasizing the continuous and interconnected nature of energy transformations in various physical systems.

Get key ideas from YouTube videos. It’s free

Recent questions

  • What is the definition of work in physics?

    Work in physics is defined as the product of force applied to an object and the displacement of that object in the direction of the force. For work to be done, both force and displacement must occur, and they must be in the same direction. The formula for calculating work is given as W = F * d * cos(θ), where W is work, F is the force applied, d is the displacement, and θ is the angle between the force and displacement vectors. If the force and displacement are parallel, maximum work is done, while if they are perpendicular, no work is done. Understanding this concept is crucial as it lays the groundwork for further studies in energy and related topics.

  • How do you calculate kinetic energy?

    Kinetic energy is calculated using the formula KE = 1/2 mv², where m represents the mass of the object and v represents its velocity. This formula indicates that the kinetic energy of an object is directly proportional to its mass and the square of its velocity. For example, if an object has a mass of 5 kg and is moving at a velocity of 10 m/s, its kinetic energy can be calculated as KE = 1/2 * 5 * (10)², resulting in 250 joules. This relationship highlights the importance of both mass and speed in determining the energy of a moving object, which is a fundamental concept in physics.

  • What is potential energy?

    Potential energy is defined as the energy stored in an object when work is done on it, particularly when it is displaced against a resisting force, such as gravity. The most common form of potential energy is gravitational potential energy, which is calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height above a reference point. For instance, lifting a 6 kg block to a height of 15 meters would store potential energy calculated as PE = 6 * 10 * 15, resulting in 900 joules. This energy is released when the object falls, converting potential energy into kinetic energy, illustrating the principle of energy conservation.

  • What is the work-energy theorem?

    The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. This can be expressed mathematically as W = ΔKE = KE_final - KE_initial. This principle emphasizes that any work performed on an object results in a change in its energy state, specifically its kinetic energy. For example, if a force does 500 joules of work on an object, its kinetic energy will increase by that amount, assuming no other forces are acting on it. This theorem is fundamental in physics as it connects the concepts of work and energy, providing a framework for analyzing motion and energy transformations.

  • How is power defined in physics?

    Power in physics is defined as the rate at which work is done or the rate of energy transfer. It is calculated using the formula P = W/t, where P is power, W is the work done, and t is the time taken to do that work. For example, if a person does 600 joules of work in 20 seconds, the power exerted can be calculated as P = 600/20, resulting in 30 watts. This concept is crucial in understanding how quickly energy is used or transferred in various systems, and it plays a significant role in applications ranging from electrical devices to mechanical systems.

Related videos

Summary

00:00

Understanding Work and Energy in Physics

  • The Wala Foundation YouTube channel offers a free comprehensive course for ninth graders, including a series of one-shot videos covering various subjects such as Physics, English, and Maths, with a focus on gradually uploading content for each chapter.
  • The current focus is on Chapter 11 of the NCERT syllabus, titled "Work and Energy," which includes the concept of power, and emphasizes the importance of understanding previous chapters like motion, loss of motion, and gravity before tackling this chapter.
  • The instructor encourages students to review any missed concepts from earlier chapters to ensure a solid foundation for understanding work and energy, as these topics are interconnected.
  • Work is defined in physics as the product of force applied to an object and the displacement of that object in the direction of the force, emphasizing that both force and displacement must occur for work to be done.
  • The relationship between force and displacement is crucial; work is only done when the force and displacement are in the same direction, and if they are not, the effective work done must be calculated using the cosine of the angle between them.
  • The formula for calculating work is given as W = F * d * cos(θ), where W is work, F is force, d is displacement, and θ is the angle between the force and displacement vectors.
  • Specific angle values are provided: if θ = 0° (force and displacement are parallel), cos(0°) = 1, resulting in maximum work; if θ = 180° (force and displacement are opposite), cos(180°) = -1, indicating work done against the force; and if θ = 90° (force is perpendicular to displacement), cos(90°) = 0, meaning no work is done.
  • The instructor highlights that work is a scalar quantity, despite being derived from the multiplication of two vector quantities (force and displacement), and it does not possess directionality like vectors do.
  • Students are advised to remember the cosine values for key angles (0°, 90°, and 180°) to facilitate calculations related to work, and they are encouraged to refer to the NCERT textbook for additional explanations and examples.
  • The lecture emphasizes the importance of understanding the concept of work in physics, as it lays the groundwork for further studies in energy and related topics, and encourages students to engage actively with the material for better comprehension.

13:20

Understanding Vectors Scalars and Work Dynamics

  • The text discusses the nature of vectors and scalars, emphasizing that not all quantities are vectors, and questioning the validity of certain rules regarding vectors in different contexts, particularly in relation to force and displacement.
  • It explains that when taking the dot product of two vectors, the result is a scalar quantity, which is why it is referred to as a scalar product, highlighting the distinction between vector and scalar quantities.
  • The concept of work is introduced, with the unit of work defined as Joules, and the relationship between force, displacement, and the angle (theta) between them is explained using the formula: Work = Force × Displacement × cos(theta).
  • An example is provided where a force of 1 Newton moves an object 1 meter in the same direction, resulting in 1 Joule of work done, illustrating the direct relationship between force, displacement, and work.
  • The text categorizes work into three types: positive work, negative work, and zero work, explaining that positive work occurs when the force and displacement are in the same direction, while negative work occurs when they are in opposite directions.
  • A practical scenario is described involving a sliding door, where the application of force results in displacement, and the relationship between the direction of force and displacement is analyzed to determine the type of work done.
  • The text discusses the concept of friction, explaining how it opposes motion and can affect the work done on an object, particularly in scenarios where applied force is greater than frictional force.
  • It emphasizes the importance of understanding the angle in the work formula, noting that a force applied in the opposite direction (180 degrees) results in negative work, which slows down the object.
  • The text concludes with a discussion on zero work, stating that if the net work done by all forces acting on an object is zero, then the object does not experience any displacement, regardless of the number of forces applied.
  • Throughout the text, the significance of understanding the relationships between force, displacement, and work is highlighted, along with the mathematical principles that govern these concepts, ensuring clarity in the application of physics principles.

28:57

Understanding Work and Force Relationships

  • The discussion begins with a contemplation of the concepts of work and force, specifically questioning the relationship between force, displacement, and the angle involved in calculating work done, using the formula \( W = F \cdot d \cdot \cos(\theta) \).
  • The speaker notes that when a force acts downwards (like gravitational force, \( MG \)), and the displacement is horizontal, the angle \( \theta \) is 90 degrees, leading to \( \cos(90) = 0 \), which results in zero work done.
  • An example is provided where a force of 50 Newtons is applied over a displacement of 2 meters, emphasizing that despite the force, if the angle is 90 degrees, the work done remains zero due to the direction of the force not contributing to the displacement.
  • The speaker encourages students to understand the importance of direction in work calculations, stating that if the force and displacement are in opposite directions (180 degrees), the work done is negative, as shown in the example of a ball being tossed upwards against gravity.
  • A practical example is given where a force of 15 Newtons is applied to push a block 20 centimeters (0.2 meters) in the same direction, resulting in a positive work calculation of \( W = 15 \cdot 0.2 \cdot \cos(0) = 3 \) Joules.
  • The speaker discusses the concept of negative work, explaining that when an object moves against the direction of the applied force (like a ball moving upwards against gravity), the work done is negative, calculated as \( W = -20 \cdot 10 \cdot 7 = -1400 \) Joules.
  • The conversation shifts to the topic of why porters are paid, despite the physics principle that if no work is done (zero work), they should not be compensated; the speaker argues that physical exertion and the effort involved should be recognized.
  • A scenario is presented where a person pulls a block with a force of 7 Newtons at an angle of 60 degrees over a distance of 3 meters, prompting the calculation of work done using the formula \( W = F \cdot d \cdot \cos(\theta) \).
  • The speaker emphasizes the need for clarity in understanding the principles of work and force, suggesting that students should pay attention to the direction of forces and displacements to grasp the concept of work done accurately.
  • The discussion concludes with a reminder that while physical work may not always result in measurable work done in physics, the effort and energy expended in tasks should still be acknowledged and compensated appropriately.

44:39

Understanding Forces Work and Energy in Physics

  • The text begins with a metaphorical description of a crooked figure and corpses crawling, suggesting a chaotic or distorted situation, possibly relating to a dog and its movement on the ground, emphasizing that a dog cannot walk in the air.
  • It introduces the concept of forces, specifically mentioning "seven newtons" and the formation of a "60-degree angle," indicating a discussion about angles and their significance in physics.
  • The speaker emphasizes the importance of remembering specific angle values such as 30, 45, 60, 90, 120, and 180 degrees, suggesting that these values are crucial for understanding trigonometry.
  • A practical example is given involving a porter lifting a 15 kg block, where the downward force is calculated to be 150 newtons, and it is questioned how much upward force is needed to lift it, indicating that the force applied must exceed 150 newtons to lift the block.
  • The text discusses the concept of work done against gravity, explaining that to lift the block 1.5 meters, the work done can be calculated using the formula: Work = Force x Displacement x cos(theta), where theta is the angle between the force and displacement.
  • It introduces a homework question involving forces acting on a block, where a forward force of 20 newtons and a backward force of 5 newtons are mentioned, indicating the need to calculate net work by summing the forces.
  • The text transitions to discussing the work done by gravity on a satellite in circular motion around the Earth, explaining that the angle between the gravitational force and the satellite's displacement is 90 degrees, resulting in zero work done by gravity.
  • The speaker explains the relationship between work and energy, stating that energy is required to do work and can be converted into different forms, emphasizing that energy is a scalar quantity.
  • Kinetic energy is defined as the energy possessed by an object in motion, with the formula for kinetic energy given as KE = 1/2 mv², where m is mass and v is velocity.
  • The text concludes with a reiteration of the formula for work done, stating that work is defined as the product of force and displacement, and emphasizes the importance of understanding these concepts in physics.

01:01:28

Understanding Work and Energy in Physics

  • Force applied to an object results in acceleration, as per Newton's second law, which states that Force (F) equals Mass (M) multiplied by Acceleration (A), or F = MA.
  • The relationship between displacement (S), initial velocity (u), final velocity (v), and acceleration (a) can be expressed using the equation 2as = v² - u², which can be rearranged to find S as S = (v² - u²) / (2a).
  • The work-energy theorem states that the work done (W) on an object is equal to the change in kinetic energy (KE), expressed as W = ΔKE = KE_final - KE_initial.
  • Kinetic energy is defined as KE = 1/2 mv², where m is mass and v is velocity. The initial kinetic energy (KE_initial) can be calculated using the initial velocity (u) and the final kinetic energy (KE_final) using the final velocity (v).
  • If an object starts from rest (initial velocity u = 0), the work done on the object can be simplified to W = 1/2 mv², indicating that all work done is converted into kinetic energy.
  • When calculating the change in kinetic energy for an object with mass (m) moving from an initial velocity (u) to a final velocity (v), the formula used is ΔKE = 1/2 m(v² - u²).
  • To find the work done on an object, one can use the work-energy theorem, which states that the work done is equal to the change in kinetic energy, thus W = KE_final - KE_initial.
  • For a mass of 5 kg changing its velocity from 10 m/s to 15 m/s, the work done can be calculated as W = 1/2 * 5 * (15² - 10²) = 625 Joules.
  • The percentage change in kinetic energy can be calculated using the formula: Percentage Change = [(KE_final - KE_initial) / KE_initial] * 100, where KE_final and KE_initial are the final and initial kinetic energies, respectively.
  • The work-energy theorem is crucial in physics as it relates the work done by all forces acting on an object to the change in its kinetic energy, emphasizing that any work done results in a change in energy state.

01:18:57

Energy Dynamics of Lifting and Lowering Objects

  • The initial calculation involves determining the value of \( \frac{1}{2} mv^2 \), where \( m \) represents mass and \( v \) represents velocity. If you perform a calculation of 100, taking \( \frac{1}{2} mv^2 \) as common, the result simplifies to 800% after subtracting 1 from 9 and multiplying the remaining 8 by 100.
  • Potential energy is defined as energy that is stored when work is done on an object. It is only stored when a force is applied to displace the object against a resisting force, such as gravity.
  • An example illustrates that if a person lifts an object from the ground, the object initially has zero potential energy. As the person applies force and displaces the object upwards, work is done, and potential energy is stored in the object.
  • Kinetic energy is introduced as the energy of motion, which is present when the object is released and falls due to gravity. The energy transferred during the lifting process is muscular energy, which converts into potential energy.
  • The relationship between potential energy and height is emphasized: the higher an object is lifted against gravity, the more potential energy it stores. This is quantified by the formula \( PE = mgh \), where \( g \) is the acceleration due to gravity.
  • The concept of gravitational potential energy is explained, indicating that energy is stored based on the object's position relative to the ground. The higher the object is raised, the greater the potential energy.
  • The text discusses the importance of position in determining potential energy, stating that energy is associated with the object's position and can change as the position changes.
  • An example calculation is provided: lifting a block of mass 6 kg to a height of 15 meters requires a force of 60 Newtons, resulting in a work done of 900 Joules (calculated as \( 60 \times 15 \)).
  • When lowering the same block from a height of 15 meters to 5 meters, the work done is calculated as negative because the force applied is in the opposite direction of the displacement, resulting in a work of -300 Joules.
  • The total work done when lifting the block to 15 meters and then lowering it to 5 meters is the sum of the positive and negative work, which is 600 Joules (900 Joules from lifting minus 300 Joules from lowering).

01:33:13

Understanding Potential Energy and Energy Transformations

  • The discussion begins with a reference to a calculation involving potential energy, specifically mentioning a value of 600 joules derived from a height of 15 meters and a drop of 5 meters, leading to a net height of 10 meters. The formula used is potential energy (PE) = mass (m) × gravitational acceleration (g) × height (h), where g is approximately 10 m/s².
  • The speaker emphasizes that potential energy is path-independent, meaning the energy depends only on the initial and final heights, not the path taken. This is illustrated by a block being raised and then lowered, where the height difference remains the same regardless of the path.
  • Two types of potential energy are introduced: gravitational potential energy, which depends on height, and configuration potential energy, which relates to the arrangement of objects, such as a stretched or compressed spring.
  • The concept of energy transformation is explained using examples like a balloon being filled with air, where the potential energy increases as air is compressed inside, and a compressed spring that releases energy when allowed to expand.
  • The law of conservation of energy is highlighted, stating that energy cannot be created or destroyed but only transformed from one form to another. This principle is illustrated with the example of food providing chemical energy that is converted into muscular energy for movement.
  • The speaker discusses various energy transformations, such as a bicycle rider converting muscular energy into kinetic energy, and the process of burning coal in a thermal power plant, where chemical energy is converted into thermal energy, then into kinetic energy, and finally into electrical energy.
  • A detailed example of a hydroelectric power plant is provided, explaining how water stored at height possesses potential energy, which is converted into kinetic energy as it falls, turning turbines that generate electricity.
  • The process of energy conversion in a thermal power plant is described, where coal's chemical energy is transformed into thermal energy through combustion, producing steam that drives turbines to generate electricity.
  • The speaker emphasizes that energy transformations are continuous and interconnected, using the analogy of a bank where energy is transferred and transformed but never lost, maintaining a fixed total energy in the universe.
  • The discussion concludes with a mention of an analytical method to prove energy conservation, suggesting that energy is always conserved through various transformations, and providing a framework for understanding potential and kinetic energy at different points in a system.

01:48:50

Conservation of Energy in Mechanical Systems

  • The total mechanical energy of a system remains constant, consisting of both kinetic and potential energy, which can be calculated at various points in the system. For example, at a height of 20 meters, the total mechanical energy is 800 joules, with potential energy decreasing as height decreases and kinetic energy increasing as the object falls.
  • When an object is dropped from a height, its initial velocity is zero, and as it falls, its speed increases due to gravitational acceleration. The displacement during the fall can be calculated using the formula \( v^2 = u^2 + 2as \), where \( u \) is the initial velocity, \( a \) is the acceleration (10 m/s²), and \( s \) is the displacement.
  • For a fall of 20 meters, the final velocity can be calculated as \( v^2 = 0 + 2 \times 10 \times 20 \), resulting in \( v^2 = 400 \), leading to a final velocity of 20 m/s.
  • The kinetic energy at point B, where the object has fallen 20 meters, is calculated using the formula \( KE = \frac{1}{2} mv^2 \). If the mass \( m \) is 10 kg, then \( KE = \frac{1}{2} \times 10 \times 400 = 2000 \) joules.
  • At point C, after falling 40 meters, the final velocity is calculated again using \( v^2 = 0 + 2 \times 10 \times 40 \), resulting in \( v^2 = 800 \), leading to a final velocity of approximately 28.28 m/s.
  • The kinetic energy at point C is calculated as \( KE = \frac{1}{2} mv^2 \), which gives \( KE = \frac{1}{2} \times 10 \times 800 = 4000 \) joules.
  • The principle of conservation of mechanical energy states that the total mechanical energy (potential + kinetic) remains constant throughout the fall, with potential energy converting into kinetic energy as the object descends.
  • Power is defined as the rate of doing work or the rate of energy transfer, calculated using the formula \( P = \frac{W}{t} \) or \( P = \frac{E}{t} \), where \( W \) is work done, \( E \) is energy transferred, and \( t \) is time.
  • In practical examples, if Allu climbs a 20-meter wall in 20 seconds with a weight of 600 N, the power exerted is calculated as \( P = \frac{600 \times 20}{20} = 600 \) watts. Ballu, who climbs the same wall in 10 seconds with a weight of 400 N, exerts \( P = \frac{400 \times 20}{10} = 800 \) watts.
  • The commercial unit of energy, often referred to as a "unit" or "kilowatt-hour," is used to measure energy consumption, with 1 unit equating to 1 kilowatt of power used for 1 hour, which is essential for billing in electricity consumption.

02:04:44

Understanding Energy Consumption and Calculations

  • Kilo Watt R electricity can be utilized for free, with each household containing approximately 200 kg of water, which can travel 200 kilometers per meter, emphasizing the importance of patience in understanding energy concepts.
  • Energy is defined in terms of water, with the unit of time measured in seconds and energy expressed in joules, highlighting the relationship between these units and the concept of energy as a function of power and time.
  • The text discusses the concept of Kilo Watt and its relation to energy consumption, explaining that 1 Kilo Watt R (or WAN unit) corresponds to a specific monetary value that varies by district, with an example of a cost of ₹2 per unit.
  • An example is provided where if electricity is consumed for 1 minute at a rate of ₹2 per unit, resulting in 800 units consumed, the total cost would be ₹1600, illustrating how to calculate electricity expenses based on unit consumption.
  • The calculation of power consumption is demonstrated using four 40-watt bulbs, where the total power consumed is calculated as 4 bulbs x 40 watts = 160 watts, leading to further calculations of energy consumption over time.
  • To convert power into energy, the formula used is Energy = Power x Time, where 160 watts over 10 hours results in 1.6 kilowatt-hours (units), emphasizing the conversion from watts to kilowatts by dividing by 1000.
  • The monthly energy consumption is calculated by multiplying daily consumption (1.6 units) by the number of days in September (30), resulting in a total of 48 units for the month, which can then be multiplied by the cost per unit to determine the total expense.
  • The relationship between kinetic energy and momentum is briefly discussed, with the formula for kinetic energy being expressed as KE = 1/2 mv², and the importance of understanding the relationship between variables in physics is emphasized for better comprehension of energy concepts.
Channel avatarChannel avatarChannel avatarChannel avatarChannel avatar

Try it yourself — It’s free.