How to determine Hybridization - s, sp, sp2, and sp3 - Organic Chemistry
More Learning Tutor・2 minutes read
Hybridization is determined by the number of groups connected to an element, with one group corresponding to an s orbital, two groups to SP, three groups to SP2, and four groups to SP3. In specific examples, a carbon with three bonds is SP2 hybridized, an oxygen with three bonds is also SP2 hybridized, and in a water molecule, the oxygen is SP3 hybridized while the hydrogen atoms are s hybridized due to being connected to one group.
Insights
- Hybridization in chemistry is categorized based on the number of groups attached to an element: one group corresponds to an s orbital, two groups to SP, three groups to SP2, and four groups to SP3.
- Specific examples showcase how carbon with three bonds and oxygen with three bonds are both SP2 hybridized, while in a water molecule, oxygen is SP3 hybridized with four connected groups, and hydrogen atoms are s hybridized with one group each.
Get key ideas from YouTube videos. It’s free
Recent questions
What determines hybridization in chemistry?
The number of groups connected to an element.
How is hybridization classified based on bonds?
One group corresponds to an s orbital, two groups to SP, three groups to SP2, and four groups to SP3.
What is the hybridization of a carbon with three bonds?
SP2 hybridized.
In chemistry, what hybridization does an oxygen with three bonds exhibit?
SP2 hybridized.
Why is oxygen in a water molecule SP3 hybridized?
It is connected to four groups, determining its hybridization.
Related videos
MJD Chemistry
Atomic orbital treatment of Benzene | ch#9 | 12th class chemistry
RicochetScience
Electronegativity
LearnoHub - Class 11, 12
Chemical Bonding Class11 One Shot | CBSE NEET JEE
Competition Wallah
IUPAC in 1 Shot | Organic Chemistry in 20 Days | Day 1 | UMMEED
LearnoHub - Class 11, 12
Organic Chemistry Class 11 | Chapter 12 NCERT CBSE NEET JEE #1