Gauss’s Law and its Derivation to determine Electric Field Intensity due to a line charge
Nepali Education YT・2 minutes read
Gauss law in electrostatics states that the total electric flux passing through any closed surface is equal to the charge enclosed divided by epsilon, allowing for the calculation of the electric field intensity due to a line charge as lambda divided by 2πrε.
Insights
- Gauss law in electrostatics relates the total electric flux to the charge enclosed within a closed surface, providing a fundamental link between charge distribution and electric fields.
- The formula lambda divided by 2πrε allows for the calculation of electric field intensity for a line charge, showcasing a specific application of Gauss law in determining field strength based on charge distribution.
Get key ideas from YouTube videos. It’s free
Recent questions
What is Gauss law in electrostatics?
Gauss law states total electric flux equals enclosed charge divided by epsilon.
How can electric field intensity due to a line charge be calculated?
Electric field intensity is lambda divided by 2πrε.
What does Gauss law determine in electrostatics?
Gauss law determines total electric flux through a closed surface.
What is the relationship between charge enclosed and electric flux in Gauss law?
Electric flux is charge enclosed divided by epsilon.
How is the electric field intensity related to Gauss law?
Electric field intensity can be determined using Gauss law for line charges.
Related videos
Physics in Depth
#6 Electric flux and Gauss' theorem | Class 11 NEB Physics | In Nepali
Michel van Biezen
Physics Ch 67.2 Advanced E&M: Electrostatics (10 of TBD) The Electric Field from a Line Charge - 3/3
Lakshya JEE
Electrostatics ONE SHOT | Class 12th Physics | JEE Mains & Advance
Atif Ahmad Official
Electric flux class 12 | 12th class physics | federal, punjab, kpk, sindh, balochistan board
SimplifiedMinds Karnataka
Electric Charges and Fields Oneshot | 2nd PUC Physics Exam 2024