Circles Class 9 in One Shot πŸ”₯ | Class 9 Maths Chapter 9 Complete Lecture | Shobhit Nirwan

Shobhit Nirwan - 9th・2 minutes read

The text emphasizes the importance of understanding fundamental circle concepts like chords, angles, and congruence for solving related problems while providing detailed explanations and proof techniques for various theorems and properties. It also includes practical applications, construction steps, and calculations to enhance comprehension and problem-solving skills in circle geometry, culminating in a comprehensive understanding of the chapter's content.

Insights

  • Meditating on the material for the first 5-10 minutes is crucial for grasping terms and concepts thoroughly.
  • Understanding the definition of a circle, chords, and arcs is fundamental for solving related questions effectively.
  • Equal arcs in a circle create equal segments, known as a semi-circular region, emphasizing the importance of equality in geometry.
  • The application of Pythagoras' theorem and understanding perpendicular bisectors are essential for determining distances and solving circle-related problems.
  • The concept of cyclic quadrilaterals, equal opposite angles, and the sum of angles in various geometric figures are key for simplifying angle calculations and proofs.

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Recent questions

  • What is the definition of a circle?

    A circle is a collection of points equidistant from a fixed point called the center.

  • How are minor and major arcs distinguished?

    Major arcs are larger and extend to the end points of the diameter, while minor arcs are smaller.

  • What is the significance of equal arcs in a circle?

    Equal arcs in a circle create equal segments, known as a semi-circular region.

  • What is the theorem regarding equal chords in a circle?

    Equal chords subtend equal angles at the center.

  • How are perpendicular bisectors utilized in circle geometry?

    Perpendicular bisectors from the center of a circle bisect chords, aiding in triangle construction.

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Summary

00:00

Mastering Circle Concepts for Effective Problem-Solving

  • The text discusses the progression from theory-based content to practical questions, emphasizing the importance of understanding the initial reading for better comprehension.
  • It highlights the significance of meditating on the material for the first 510 minutes to grasp the terms and concepts thoroughly.
  • The text encourages careful attention to the reading and understanding of concepts, ensuring that all questions become manageable.
  • It introduces a video tutorial on the demanding Chapter Circle for class ninth, focusing on proofs, theorems, and practical problem-solving.
  • The video tutorial stresses the need for a clear understanding of the chapter's concepts, promising confidence in solving any related questions.
  • It explains the definition of a circle as a collection of points at a fixed distance from a fixed point, known as the center, and the importance of the radius in defining the circle.
  • The text clarifies the concept of a chord as a line joining any two points on the circle and a diameter as a chord passing through the center, with the diameter being twice the radius.
  • It distinguishes between minor and major arcs, explaining that the major arc is larger and extends to the end points of the diameter, while the minor arc is smaller.
  • The text emphasizes the significance of equal arcs, which are formed when arcs are created from the end points of the diameter, highlighting their equality.
  • It concludes by reinforcing the importance of understanding these fundamental concepts for a comprehensive grasp of the chapter on circles.

12:00

Circle Segments and Sectors: A Brief Explanation

  • The arches became equal and were named Semi Circle by people worldwide.
  • A piece of a circle that is half of a circle is called a semi circle.
  • The circle was divided into segments by a chord, creating minor and major segments.
  • The smaller part of the circle divided by the chord is called the minor segment.
  • The larger part of the circle divided by the chord is called the major segment.
  • Equal arcs in a circle create equal segments, known as a semi circular region.
  • A sector is a part of a circle created by joining the end points of an arc to the center.
  • The smaller part of a sector is called the minor sector, while the larger part is called the major sector.
  • Equal sectors are created by joining equal arcs from the center, forming equal sectors.
  • An angle formed by a chord at a point on a circle is called an angle stand by chord at a point.

24:34

Circle Chords and Angles Theorems Explained

  • Equal chords are chords that are equal in length.
  • Equal chords subtend equal angles at the center.
  • If two chords are equal, the angles they subtend at the center are also equal.
  • The main theorem states that if two chords are equal, the angles they subtend at the center are also equal.
  • To prove this theorem, triangles are used to show congruence.
  • The radius of a circle is equal from the center to any point on the circumference.
  • Using the side-angle-side rule, triangles can be proven congruent.
  • The converse of the main theorem states that if two chords have equal angles at the center, the chords themselves are also equal.
  • Another theorem involves perpendiculars from the center of a circle bisecting chords.
  • Understanding the properties of chords, angles, and congruence in circles is essential for solving related problems.

40:39

Constructing Triangles for Circle Problems

  • Shobhit bhaiya advises constructing a triangle when facing circle-related questions.
  • To construct a triangle, join points O and B with the radius.
  • The angles in triangles O and OB are equal due to the common side and angle-side-side rule.
  • The Right Angle Hypotenuse Side (RHS) congruence rule states that right angles, hypotenuses, and one side being equal in two triangles make them congruent.
  • The perpendicular from the center of a circle bisects a chord, leading to two triangles.
  • The theorem states that a line drawn through the center to bisect a chord is perpendicular to the chord.
  • The converse of the theorem implies that a right angle is formed when a line is drawn through the center to bisect a chord.
  • To prove an angle is 90 degrees, use the linear pair concept or interior angles on parallel lines.
  • The concept of making triangles congruent and using perpendicular bisectors is crucial in circle-related problems.
  • Remember the four theorems discussed, including equal chords creating equal angles and perpendicular bisectors bisecting chords.

55:33

Calculating Perpendicular Distance Between Chords

  • The radius given is 13 centimeters, and the length of the chord is 10 centimeters.
  • The chord of length 10 is a rod, and the length of the link is to be determined.
  • The distance of the chord from the center is to be found.
  • Perpendicular distance is crucial in determining the distance from a point to a line.
  • The Pythagorean theorem is applied to find the unknown side in a right-angled triangle.
  • Given values include a radius of 13 cm and a chord length of 10 cm.
  • The Pythagorean theorem is utilized to calculate the unknown side in a right-angled triangle.
  • The perpendicular distance between two parallel chords is found by bisecting the chord perpendicularly from the center.
  • The distance between the chords is determined by constructing right-angled triangles and applying the Pythagorean theorem.
  • The perpendicular distance between the chords is calculated to be 2 centimeters.

01:10:45

Calculating Distance Between Points: A Step-by-Step Guide

  • To distinguish between big and small, 16 is identified as the larger side.
  • The side marked as 16 is determined to be the larger one.
  • The total distance between two points is calculated as 16 units.
  • The process of calculating the distance between two points is explained.
  • Instructions on how to calculate the distance and draw a circle are provided.
  • The method of finding the distance between two points is detailed.
  • Construction steps are outlined to aid in determining the distance between points.
  • The process of constructing a triangle is described for clarity.
  • The application of Pythagoras' theorem in determining distances is explained.
  • The final calculation results in a distance of 14 cm between the two points.

01:26:04

Solving Equations and Proving Circle Centers

  • The initial problem involves solving for x and y in a mathematical equation.
  • The solution includes finding the value of y as 24/5.
  • The final answer is determined to be 48/5.
  • The next question involves proving that the centers of two circles lie on the perpendicular bisector of a common chord.
  • The proof requires showing that the line joining the centers is perpendicular to the common chord.
  • The concept to remember is that when two circles intersect, the line joining their centers is the perpendicular bisector of the common chord.
  • The practical application involves applying this concept to solve a question about intersecting circles.
  • The key is to understand the theory and apply it to prove the perpendicular bisector relationship.
  • The process is simplified by focusing on the main concept and applying it to the given problem.
  • The final step is to quickly solve the question using the explained concept.

01:41:39

Circle Chord Length Theorem Proof Triangle

  • The task is to find the length of a common chord between two circles.
  • Given that r1 is 5 cm, r2 is 3 cm, and OK is 4 cm.
  • The common chord will be the perpendicular bisector of the line joining the centers of the circles.
  • Construct a triangle by joining points O, A, and B.
  • The length of the common chord will be 6 cm.
  • The theorem states that equal chords of a circle are equidistant from the center.
  • Construction involves joining points O and D to prove the theorem.
  • The distance from the center to the chord will be equal if the chords are equal.
  • The converse theorem states that if the distance from the center is equal, the chords will be equal.
  • Construction and proof involve joining points O and D to establish the equality of chords based on equal distances from the center.

01:56:11

Proving Chord Equality in Circles

  • If chords Kadi and Pub are bisected at point A, and 2PB is labeled as A and 2, then the link between them is referred to as the link.
  • The theorem states that if two chords in a circle are equal, then their distance from the center will also be equal.
  • The converse of the theorem indicates that if the distance from the center to a chord is equal to two chords, then the chords are equal.
  • To prove the equality of two chords intersecting within a circle, the perpendicular distances from the center to the chords are compared.
  • By proving that the perpendicular distances from the center to the chords are equal, the equality of the chords can be established.
  • Constructing triangles and applying the RHS congruence rule helps in proving the equality of the chords.
  • If the chords are equal, then the distances from the center to the chords are also equal.
  • Halving the chords and comparing the halves helps in proving the equality of the chords.
  • By carefully analyzing the given information and applying mathematical principles, the equality of the chords can be demonstrated.
  • The process involves logical thinking, construction of triangles, and application of congruence rules to establish the equality of the chords.

02:12:31

Equalizing Parts in Geometry Theorems Explained

  • Congress has been equalized, with parts being half and half, making them equal.
  • Equalizing and adding to both parts ensures they remain equal.
  • The concept of halves being equal is emphasized.
  • The process of adding and equalizing parts is detailed.
  • The text discusses writing half of A and B, and the concept of making parts equal.
  • The importance of understanding the concept is highlighted.
  • The text delves into the theorem regarding angles inclined by an arc on a circle.
  • The angle subtended by an arc at the center is discussed.
  • The text explains the theorem that the angle subtended by an arc at the center is double the angle subtended at any remaining part of the circle.
  • The angle in a semi-circle is established to always be 90 degrees.

02:26:22

Triangle Properties and Angle Measurements Explained

  • Equal radius o will be equal to both Radius and if of any triangle Opposite sides of a triangle are equal
  • Angle o will be equal to England a brother, which is 30 degrees
  • Angle a s is 70 degrees
  • Angle CBD will be equal to 30 degrees
  • Equilateral Triangle COD E has angle a e at 60 degrees
  • Arc CD at the center makes 60 degrees, while on the remaining circle it makes 30 degrees
  • The reflex angle BOD is 220 degrees
  • The angle subtended by arc BCD is 140 degrees
  • The sum of angles AD and AC is 180 degrees, proving collinearity
  • The angle in semi circle is 90 degrees, leading to the proof of collinearity of points B, D, and C

02:41:44

Circle Formation and Angle Properties

  • If two angles of a segment are equal, then the segment will form a circle.
  • Four points on a circle will be formed if a line segment makes equal angles.
  • The four points will lie on the circle if they are brought to it.
  • The same side of the line containing the line segment will have the four points lying on the circle.
  • Angles in the same segment are equal.
  • To find an angle quickly, apply the angle sum property.
  • The angle BDC will be equal to 80 degrees.
  • The angle DC will be equal to 110 degrees.
  • The sum of opposite angles in a cyclic quadrilateral is 180 degrees.
  • The internal angle bisector of any quadrilateral forms a cyclic quadrilateral.

02:56:24

Circle Theorems: Mastering Angles in Geometry

  • 180 becomes 180 when placed in a specific position, forming 360 - 180, which equals f.
  • The sum of f and angle A is 360, with f being 180 when placed elsewhere.
  • The sum of 180 and the angle of the edge is 180, proving the angles are equal.
  • AG Kazi plus Angle Easy Kazi's proof should also be 180 degrees.
  • Cyclic quadrilaterals have opposite angles summing to 180, proven through various angle manipulations.
  • Understanding the properties of cyclic quadrilaterals aids in solving angle-related questions easily.
  • In a cyclic quadrilateral, the angles opposite each other are equal, leading to easy angle calculations.
  • Vertically opposite angles are equal, simplifying angle calculations in various geometric figures.
  • Thorough revision of circle chapter theorems and properties is essential for mastering the topic.
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